-.02x^2=1.12x=12

Solution for -.02x^2=1.12x=12 equation:

-.02x^2=1.12x=12

We move all terms to the left:

-.02x^2-(1.12x)=0

We add all the numbers together, and all the variables

-.02x^2-(+1.12x)=0

We add all the numbers together, and all the variables

-0.02x^2-(+1.12x)=0

We get rid of parentheses

-0.02x^2-1.12x=0

a = -0.02; b = -1.12; c = 0;
Δ = b2-4ac
Δ = -1.122-4·(-0.02)·0
Δ = 1.2544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.12)-\sqrt{1.2544}}{2*-0.02}=\frac{1.12-\sqrt{1.2544}}{-0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.12)+\sqrt{1.2544}}{2*-0.02}=\frac{1.12+\sqrt{1.2544}}{-0.04}
$